Thermodynamics Question 140

Question: In a thermodynamics process, pressure of a fixed mass of a gas is changed in such a manner that the gas releases 20 J of heat and 8J of work is done on the gas. If the initial internal energy of the gas was 30J. The final internal energy will be

[DPMT 2002]

Options:

A) 18J

B) 9J

C) 4.5J

D) 36J

Show Answer

Answer:

Correct Answer: A

Solution:

Given $ \Delta Q=-20J, $

$ \Delta W=-8J $ and $ U _{1}=30J $

$ \Delta Q=\Delta U+\Delta W $

Therefore $ \Delta U=(\Delta Q-\Delta W) $

Therefore $ (U _{f}-U _{i}) $ = $ (U _{f}-30)=-20-(-8) $

Therefore $ U _{f}=18J $



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