SATHEE: Thermodynamics Question 139

Thermodynamics Question 139

Question: If heat given to a system is 6 kcal and work done is 6 kJ. Then change in internal energy is

[BHU Med. 2000]

Options:

A) 19.1 kJ

B) 12.5 kJ

C) 25 kJ

D) Zero

Show Answer

Answer:

Correct Answer: A

Solution:

$Δ Q = Δ U + Δ W$

Therefore $Δ U = Δ Q - Δ W$

$= 6 \times 4.18 - 6 = 19.08 k J$

$\approx 19.1 k J$

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Thermodynamics Question 139

Question: If heat given to a system is 6 kcal and work done is 6 kJ. Then change in internal energy is

Options:

Answer:

Solution:

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