Thermodynamics Question 139
Question: If heat given to a system is 6 kcal and work done is 6 kJ. Then change in internal energy is
[BHU Med. 2000]
Options:
A) 19.1 kJ
B) 12.5 kJ
C) 25 kJ
D) Zero
Show Answer
Answer:
Correct Answer: A
Solution:
$ \Delta Q=\Delta U+\Delta W $
Therefore $ \Delta U=\Delta Q-\Delta W $
$ =6\times 4.18-6=19.08kJ $
$ \approx 19.1kJ $
