Thermodynamics Question 132

Question: In a thermodynamic process, pressure of a fixed mass of a gas is changed in such a manner that the gas molecules gives out 20 J of heat and 10 J of work is done on the gas. If the initial internal energy of the gas was 40 J, then the final internal energy will be

[DPMT 2004]

Options:

A) 30 J

B) 20 J

C) 60 J

D) 40 J

Show Answer

Answer:

Correct Answer: C

Solution:

$ \Delta Q=\Delta U+\Delta W=(U _{f}-U _{i})+\Delta W $

Therefore $ 30=(U _{f}-40)+10 $

Therefore $ U _{f}=60J $



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