SATHEE: Thermodynamics Question 127

Thermodynamics Question 127

Question: In a given process for an ideal gas, $d W = 0$ and $d Q < 0.$ Then for the gas

[IIT-JEE (Screening) 2001]

Options:

A) The temperature will decrease

B) The volume will increase

C) The pressure will remain constant

D) The temperature will increase

Show Answer

Answer:

Correct Answer: A

Solution:

From FLOT

Therefore $d U = d Q - d W \Rightarrow d U = d Q (< 0)$

$(∵ d W = 0)$

$\Rightarrow d U < 0$ So temperature will decrease.

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Thermodynamics Question 127

Question: In a given process for an ideal gas, dW=0 and dQ<0. Then for the gas

Options:

Answer:

Solution:

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Question: In a given process for an ideal gas, $d W = 0$ and $d Q < 0.$ Then for the gas