Thermodynamics Question 121

Question: In thermodynamic process, 200 Joules of heat is given to a gas and 100 Joules of work is also done on it. The change in internal energy of the gas is

[AMU (Engg.) 1999]

Options:

A) 100 J

B) 300 J

C) 419 J

D) 24 J

Show Answer

Answer:

Correct Answer: B

Solution:

ΔQ=ΔU+ΔW ;

ΔQ=200J and ΔW=100J

Therefore ΔU=ΔQΔW=200(100)=300J



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