Thermodynamics Question 12
Question: The amount of work done in an adiabatic expansion from temperature T to $ T _{1} $ is
[MP PMT 1989]
Options:
A) $ P{{T}^{\gamma }}= $ constant
B) $ P{{T}^{-1+\gamma }}= $ constant
C) $ {{P}^{\gamma -1}}{{T}^{\gamma }}= $ constant
D) $ {{P}^{1-\gamma }}{{T}^{\gamma }}= $ constant
Show Answer
Answer:
Correct Answer: D
Solution:
$ P{{V}^{\gamma }}= $ constant
Therefore $ P{{( \frac{RT}{P} )}^{\gamma }}= $ constant
Therefore $ {{P}^{1-\gamma }}{{T}^{\gamma }}= $ constant.
