Thermodynamics Question 118
Question: When the amount of work done is 333 cal and change in internal energy is 167 cal, then the heat supplied is
[AFMC 1998]
Options:
A) 166 cal
B) 333 cal
C) 500 cal
D) 400 cal
Show Answer
Answer:
Correct Answer: C
Solution:
$ \Delta Q=\Delta U+\Delta W=167+333=500\ cal $