Thermodynamics Question 118

Question: When the amount of work done is 333 cal and change in internal energy is 167 cal, then the heat supplied is

[AFMC 1998]

Options:

A) 166 cal

B) 333 cal

C) 500 cal

D) 400 cal

Show Answer

Answer:

Correct Answer: C

Solution:

$ \Delta Q=\Delta U+\Delta W=167+333=500\ cal $



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