Thermodynamics Question 116
Question: 110 J of heat is added to a gaseous system, whose internal energy change is 40 J, then the amount of external work done is
[CBSE PMT 1993; DPMT 1996, 03; AFMC 1999; JIPMER 2000; MH CET 2000; Pb. PMT 2003]
Options:
A) 150 J
B) 70 J
C) 110 J
D) 40 J
Show Answer
Answer:
Correct Answer: B
Solution:
$ \Delta Q=\Delta U+\Delta W $
Therefore $ \Delta W=\Delta Q-\Delta U=100-40=70J $
