Thermodynamics Question 113

Question: Find the change in internal energy of the system when a system absorbs 2 kilocalorie of heat and at the same time does 500 joule of work

[EAMCET 1984]

Options:

A) 7900 J

B) 8200 J

C) 5600 J

D) 6400 J

Show Answer

Answer:

Correct Answer: A

Solution:

$ \Delta Q=2kcal=2\times 10^{3}\times 4.2J $

$ =8400J $ and $ \Delta W=500J. $

Hence from $ \Delta Q=\Delta U+\Delta W, $

$ \Delta W=\Delta Q-\Delta U $ = 8400 - 500 = 7900 J



NCERT Chapter Video Solution

Dual Pane