Thermodynamics Question 113

Question: Find the change in internal energy of the system when a system absorbs 2 kilocalorie of heat and at the same time does 500 joule of work

[EAMCET 1984]

Options:

A) 7900 J

B) 8200 J

C) 5600 J

D) 6400 J

Show Answer

Answer:

Correct Answer: A

Solution:

ΔQ=2kcal=2×103×4.2J

=8400J and ΔW=500J.

Hence from ΔQ=ΔU+ΔW,

ΔW=ΔQΔU = 8400 - 500 = 7900 J



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