Thermodynamics Question 110
Question: A system is given 300 calories of heat and it does 600 joules of work. How much does the internal energy of the system change in this process (J = 4.18 joules/cal)
[MP PET 1991]
Options:
A) 654 Joule
B) 156.5 Joule
C) ? 300 Joule
D) ? 528.2 Joule
Show Answer
Answer:
Correct Answer: A
Solution:
$ J\Delta Q=\Delta U+\Delta W,\ \ \Delta U=J\Delta Q-\Delta W $
$ \Delta U=4.18\times 300-600=654\ Joule $
