Thermodynamics Question 108
Question: A thermodynamic system goes from states (i) $ P _{1} $ , V to $ 2P _{1} $ , V (ii) P, V to P, 2V. Then work done in the two cases is
[MP PMT 1990]
Options:
A) Zero, Zero
B) Zero, $ PV _{1} $
C) $ PV _{1} $ , Zero
D) $ PV _{1},\ P _{1}V _{1} $
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Answer:
Correct Answer: B
Solution:
(i) Case $ \to $ Volume = constant $ \Rightarrow \int _{{}}^{{}}{PdV}=0 $ (ii)
Case $ \to $ P = constant $ \Rightarrow \int _{V _{1}}^{2V _{1}}{PdV}=P\int _{V _{1}}^{2V _{1}}{dV=PV _{1}} $
