Thermodynamics Question 105
Question: In changing the state of thermodynamics from A to B state, the heat required is Q and the work done by the system is W. The change in its internal energy is
[MP PMT 1986; AMU (Med.) 2001]
Options:
A) Q + W
B) Q ? W
C) Q
D) $ \frac{Q-W}{2} $
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Answer:
Correct Answer: B
Solution:
$ \Delta Q=\Delta U+\Delta W $
Therefore $ \Delta U=\Delta Q-\Delta W=Q-W $ (using proper sign)
