Thermodynamics Question 103

Question: For the reaction H2(g)+12O2(g)→H2O(l),ΔH=−285.8kJmol−1 ΔS=−0.163kJmol−1K−1. What is the value of free energy change at 27oC for the reaction? [KCET 1999]

Options:

A) −236.9kJmol−1

B) −281.4kJmol−1

C) −334.7kJmol−1

D) +334.7kJmol−1

Show Answer

Answer:

Correct Answer: A

Solution:

ΔG=ΔH−TΔS,T=27+273=300K

ΔG=(−285.8)−(300)(−0.163)=−236.9kJmol−1

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