Rotational Motion Question 97
Question: Two particles of mass 5 kg and 10 kg respectively are attached to the two ends of a rigid rod of length 1 m with negligible mass.The centre of mass of the system from the 5 kg particle is nearly at a distance of:
Options:
A) 50 cm
B) 67 cm
C) 80 cm
D) 33 cm
Show Answer
Answer:
Correct Answer: B
Solution:
-
[b]
$ X _{cm}=\frac{m _1x _1+m _2x _2}{m _1+m _2} $
$ =\frac{5\times 0+100\times 10}{5+10}=\frac{200}{3}=66.66cm $
$ X _{cm}\simeq 67cm $