Rotational Motion Question 78

Question: A rod PQ of mass M and length L is hinged at end P. The rod is kepts horizontal by a massless string tied to point Q . When string is cut, the initial angular acceleration of the rod is

Options:

A) 3g2L

B) gL

C) 2gL

D) 2g3L

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Answer:

Correct Answer: A

Solution:

  • Torque on the rod = Moment of weight of the rod about P

    τ=mgL2 ….(i)

    Moment of inertia of rod about

    P=ML23 ….(ii)

    As τ=la

    From Eqs.(i) and (ii), we get

    MgL2=ML23α

    α=3g2L



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