SATHEE: Rotational Motion Question 70

Rotational Motion Question 70

Question: A thin circular ring of mass M and radius r is rotating about its axis with constant angular velocity $ω$ . Two objects each of mass m are attached gently to the opposite ends of a diameter of the ring. The ring now rotates with angular velocity given by

[AIPMT (M) 2010]

Options:

A) $\frac{(M + 2 m) ω}{2 m}$

B) $\frac{(M + 2 m) ω}{2 m}$

C) $\frac{(M + 2 m) ω}{M}$

D) $\frac{M ω}{M + 2 m}$

Show Answer

Answer:

Correct Answer: D

Solution:

In the absence of external torque, angular momentum remain constant

$L = I ω = I^{'} ω^{'}$

$∴$ $M R^{2} ω = (M + 2 m) R^{2} ω^{'}$

$ω ‘ = \frac{M ω}{(M + 2 m)}$

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Rotational Motion Question 70

Question: A thin circular ring of mass M and radius r is rotating about its axis with constant angular velocity ω . Two objects each of mass m are attached gently to the opposite ends of a diameter of the ring. The ring now rotates with angular velocity given by

Options:

Answer:

Solution:

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Question: A thin circular ring of mass M and radius r is rotating about its axis with constant angular velocity $ω$ . Two objects each of mass m are attached gently to the opposite ends of a diameter of the ring. The ring now rotates with angular velocity given by