Rotational Motion Question 7

Question: A particle performing uniform circular motion has angular momentum L. If its angular frequency is doubled and its kinetic energy halved, then the new angular momentum is

[AIEEE 2003]

Options:

A) L4

B) 2L

C) 4L

D) L2

Show Answer

Answer:

Correct Answer: A

Solution:

  • [a] Angular momentum L=lω (i)

    Kinetic energy K=12lω2=12Lω [from Eq.(i)]

    ∴ L=2Kω

    Now, the new angular momentum

    L′=2(K2)2ω

    (∵K′=K2andω‘=2ω)

    ⇒ L′=L4

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