Rotational Motion Question 66

Question: A thin rod of length L and mass M is bent at its midpoint into two halves so that the angle between them is $ 90^{o} $ . The moment of inertia of the bent rod about an axis passing through the bending point and perpendicular to the plane defined by the two halves of the rod is

[AIPMPT (S) 2008]

Options:

A) $ \frac{ML^{2}}{24} $

B) $ \frac{ML^{2}}{12} $

C) $ \frac{ML^{2}}{6} $

D) $ \frac{\sqrt{2}ML^{2}}{24} $

Show Answer

Answer:

Correct Answer: B

Solution:

  • Since rod is bent at the middle, so each part of it will have same length $ ( \frac{L}{2} ) $ and mass $ ( \frac{M}{2} ) $ as shown.

    Moment of inertia of each part through its one end $ =\frac{1}{3}( \frac{M}{2} ){{( \frac{L}{2} )}^{2}} $

    Hence, net moment of inertia through its middle point O is

    $ I=\frac{1}{3}( \frac{M}{2} ){{( \frac{L}{2} )}^{2}}+\frac{1}{3}( \frac{M}{2} ){{( \frac{L}{2} )}^{2}} $

    $ =\frac{1}{3}[ \frac{ML^{2}}{8}+\frac{ML^{2}}{8} ]=\frac{ML^{2}}{12} $



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Dual Pane