Rotational Motion Question 65

Question: The ratio of the radii of gyration of a circular disc to that of a circular ring, each of same mass and radius, around their respective axes is

[AIPMPT (S) 2008]

Options:

A) $ \sqrt{3}:\sqrt{2} $

B) $ 1:\sqrt{2} $

C) $ \sqrt{2}:1 $

D) $ \sqrt{2}:\sqrt{3} $

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Answer:

Correct Answer: B

Solution:

  • Key Idea: The square root of the ratio of the moment of inertia of a rigid body and its mass is called radius of gyration.

    As in key idea, radius of gyration is given by

    $ K=\sqrt{\frac{I}{M}} $ For given problem

    $ \frac{K _{disc}}{K _{ring}}=\sqrt{\frac{I _{disc}}{I _{ring}}} $

    But $ I _{disc} $ (about its axis) $ =\frac{1}{2}MR^{2} $

    and $ I _{ring} $ (about its axis) $ =MR^{2} $ where R is the radius of both bodies.

    Therefore, Eq.

    (i) becomes

    $ \frac{K _{disc}}{K _{ring}}=\sqrt{\frac{\frac{1}{2}MR^{2}}{MR^{2}}}=1:\sqrt{2} $



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