Rotational Motion Question 64

Question: A particle of mass m moves in the XY plane with a velocity v along the straight line AB. if the angular momentum of the particle with respect to origin O is $ L _{A} $ when it is at A and $ L _{B} $ when it is at B, then:

[AIPMT (S) 2007]

Options:

A) $ L _{A}>L _{B} $

B) $ L _{A}=L _{B} $

C) the relationship between $ L _{A} $ and $ L _{B} $ depends upon the slope of the line AB

D) $ L _{A}<L _{B} $

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Answer:

Correct Answer: B

Solution:

  • From the definition of angular momentum,

    $ \vec{L}=\vec{r}\times \vec{p}=rmv\sin \phi (-\vec{k}) $

    Therefore, the magnitude of L is

    $ L=mvr\sin \phi =mvd $

    where $ d=r\sin \phi $ is the distance of closest approach of the particle to the origin.

    As d is same for both the particles, hence $ L _{A}=L _{B} $ .



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