SATHEE: Rotational Motion Question 43

Rotational Motion Question 43

Question: ABC is a right angled triangular plate of uniform thickness. The sides are such that $A B > B C$ . $I_{1}, I_{2}, I_{3}$ are moments of inertia about AB, BC and AC respectively. Then which of the following relations is correct?

[AIPMT 2000]

Options:

A) $I_{1} = I_{2} = I_{3}$

B) $I_{2} > I_{1} > I_{3}$

C) $I_{3} < I_{2} < I_{1}$

D) $I_{3} > I_{1} > I_{2}$

Show Answer

Answer:

Correct Answer: B

Solution:

The moment of inertia of a body about an axis depends not only on the mass of the body, but also on the distribution of mass about the axis.

For a given body mass is same, so it will depend only on the distribution of mass about the axis. The mass is farthest from axis BC, so $I_{2}$ is maximum.

Mass is nearest to axis AC, so $I_{3}$ is minimum. Hence, the correct sequence will be $I_{2} > I_{1} > I_{3}$ Note: In a rotational motion, moment of inertia is also known as rotational inertia.

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Rotational Motion Question 43

Question: ABC is a right angled triangular plate of uniform thickness. The sides are such that AB>BC . I1,I2,I3 are moments of inertia about AB, BC and AC respectively. Then which of the following relations is correct?

Options:

Answer:

Solution:

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Question: ABC is a right angled triangular plate of uniform thickness. The sides are such that $A B > B C$ . $I_{1}, I_{2}, I_{3}$ are moments of inertia about AB, BC and AC respectively. Then which of the following relations is correct?