Rotational Motion Question 40

Question: The moment of inertia of a disc of mass M and radius R about a tangent to its rim in its plane is:

[AIPMT 1999]

Options:

A) 23MR2

B) 32MR2

C) 45MR2

D) 54MR2

Show Answer

Answer:

Correct Answer: D

Solution:

  • Moment of inertia of a disc about its diameter is

    Id=14MR2

    Now, according to perpendicular axis theorem moment of inertia of disc about a tangent passing through rim and in the plane of discs

    I=Id+MR2

    =14MR2+MR2

    =54MR2



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