SATHEE: Rotational Motion Question 4

Rotational Motion Question 4

Question: Moment of inertia of a circular wire of mass M and radius R about its diameter is

[AIEEE 2002]

Options:

A) $M R^{2} / 2$

B) $M R^{2}$

C) $2 M R^{2}$

D) $M R^{2} / 4$

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Answer:

Correct Answer: A

Solution:

[a] Moment of inertia of circular wire about its axis is $M R^{2}$ .

Consider two diameters $X X^{'}$ and $Y Y^{'}$ moment of inertia about any of this diameter is same let us say $l$ . From perpendicular axis theorem, $l + l = M R^{2}$ $l = \frac{M R^{2}}{2}$

Rotational Motion Question 4

Question: Moment of inertia of a circular wire of mass M and radius R about its diameter is

Options:

Answer:

Solution:

Engineering Preparation

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NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

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Sample Mock Test

Mentorship

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Rotational Motion Question 4

Question: Moment of inertia of a circular wire of mass M and radius R about its diameter is

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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