Rotational Motion Question 4

Question: Moment of inertia of a circular wire of mass M and radius R about its diameter is

[AIEEE 2002]

Options:

A) $ MR^{2}/2 $

B) $ MR^{2} $

C) $ 2MR^{2} $

D) $ MR^{2}/4 $

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Answer:

Correct Answer: A

Solution:

  • [a] Moment of inertia of circular wire about its axis is $ MR^{2} $ .

Consider two diameters $ XX’ $ and $ YY’ $ moment of inertia about any of this diameter is same let us say $ l $ . From perpendicular axis theorem, $ l+l=MR^{2} $ $ l=\frac{MR^{2}}{2} $



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