Rotational Motion Question 33

Question: A particle of mass 2 kg is moving such hat at time t, its position, in meter, is given by r(t)=5i^2t2^j^. The angular momentum of the particle at t=2s about the origin in kg m2^ s2^ is:

[JEE ONLINE 23-04-2013]

Options:

A) 80k^

B) (10i^16j^)

C) 40k^

D) 40k^ ­­

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Answer:

Correct Answer: A

Solution:

  • [a] Angular momentum

P=mv=mdrdt=2(4t)j^=16j^

putting t=2 r=5i^8j^L=rxp

Substituting,L=(5i^8j^)x(16j^)L=80k^



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