Rotational Motion Question 32

Question: A tennis ball (treated as hollow spherical shell) starting from O rolls down a hill. At point A the ball becomes air borne leaving at an angle of 300 with the horizontal. The ball strikes the ground at B. What is the value of the distance AB? (Moment of inertia of spherical shell of mass m and radius R about its diameter =23mR2)

[JEE ONLINE 22-04-2013]

Options:

A) 1.87 m

B) 2.08 m

C) 1.57 m

D) 1.77 m

Show Answer

Answer:

Correct Answer: B

Solution:

  • [b] Velocity of the tennis ball on the surface of the earth or ground v = 2gh1+k2R2(where k = radius of gyration of spherical shell = 23)R

Horizontal range AB=v2sin2θ=

2gh1+k2R2sin(2×30)g=2.08m



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