SATHEE: Rotational Motion Question 26

Rotational Motion Question 26

Question: A solid sphere is rolling on a surface , with a translational velocity $v m s^{- 1} .$ If it is to climb the inclined surface continuing to roll without slipping, then minimum velocity for this to happen is

[JEE ONLINE 12-05-2012]

Options:

A) $\sqrt{2 g h}$

B) $\sqrt{\frac{7}{5} g h}$

C) $\sqrt{\frac{7}{2} g h}$

D) $\sqrt{\frac{10}{7} g h}$

Show Answer

Answer:

Correct Answer: D

Solution:

[d] Minimum velocity for a body rolling without slipping For solid sphere,

$\frac{1}{2} m v^{2} + \frac{1}{2} I ω^{2} = m g h$

$\frac{1}{2} m v^{2} + \frac{1}{2} (\frac{2}{5} m r^{2}) (\frac{v^{2}}{r^{2}}) = m g h$

$\frac{v^{2}}{2} + \frac{2 v^{2}}{10} = g h$

$\frac{5 v^{2}}{2} + \frac{2 v^{2}}{10} = g h \Rightarrow v^{2} = \frac{10}{7} g h$

$v \geq \sqrt{\frac{10}{7} g h}$

Rotational Motion Question 26

Question: A solid sphere is rolling on a surface , with a translational velocity $v m s^{- 1} .$ If it is to climb the inclined surface continuing to roll without slipping, then minimum velocity for this to happen is

Options:

Answer:

Solution:

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Rotational Motion Question 26

Question: A solid sphere is rolling on a surface , with a translational velocity vms−1. If it is to climb the inclined surface continuing to roll without slipping, then minimum velocity for this to happen is

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: A solid sphere is rolling on a surface , with a translational velocity $v m s^{- 1} .$ If it is to climb the inclined surface continuing to roll without slipping, then minimum velocity for this to happen is