Rotational Motion Question 24
Question: A diatomic molecule is made of two masses $ m _1 $ and $ m _2 $ which are separated by a distance r. If we calculate its rotational energy by applying Bohrs rule of angular momentum quantization, its energy will be given by: (n is an integer)
[AIEEE 2012]
Options:
A) $ \frac{{{(m _1+m _2)}^{2}}n^{2}h^{2}}{2m_1^{2}m_2^{2}r^{2}} $
B) $ \frac{n^{2}h^{2}}{2(m _1+m _2)r^{2}} $
C) $ \frac{2n^{2}h^{2}}{(m _1+m _2)r^{2}} $
D) $ \frac{(m _1+m _2)n^{2}h^{2}}{2m _1m _2r^{2}} $
Show Answer
Answer:
Correct Answer: D
Solution:
- [d] $ \frac{(m _1+m _2)n^{2}h^{2}}{2m _1m _2r^{2}} $
