Rotational Motion Question 23
Question: A mass m hangs with the help of a string wrapped around a pulley on a frictionless bearing. The pulley has mass m and radius R. Assuming pulley to be a perfect uniform circular disc, the acceleration of the mass m, if the string does not slip on the pulley, is
[AIEEE 2011]
Options:
A) $ \frac{g}{3} $
B) $ \frac{3}{2}g $
C) g
D) $ \frac{2}{3}g $
Show Answer
Answer:
Correct Answer: D
Solution:
-
[d] mg−T=ma
TR=$\frac {mR^2a}{2}$
T=$\frac{mRa}{2}$=m$a^2$
$\frac{3ma}{2}$=mg
$a=\frac{2g}{3}$
