Rotational Motion Question 222

Question: The free end of a thread wound on a bobbin is passed round a nail A hammered into the wall. The thread is pulled at a constant velocity. Assuming pure rolling of bobbin, find the velocity $v _{0}$ of the centre of the bobbin at the instant when the thread forms an angle a with the vertical.

Options:

A) $\frac{vR}{R\sin \alpha -r}$

B) $\frac{vR}{R\sin \alpha +r}$

C) $\frac{2vR}{R\sin \alpha +r}$

D) $\frac{v}{R\sin \alpha +r}$

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Answer:

Correct Answer: A

Solution:

[a] When the thread is pulled, the bobbin rolls to the right.

Resultant velocity of point B along the thread is $v=v _{0}\sin \alpha -\omega r$,

where $v _{0}\sin \alpha $ is the component of translational velocity along the thread $\omega r$ linear velocity due to rotation.

As the bobbin rolls without slipping, $v _{0}=\omega R$.

Solving the obtained equations, we get

$v _{0}=\frac{vR}{R\sin \alpha -r}$



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