Rotational Motion Question 217

Question: A tangential force of 20 N is applied on a cylinder of mass 4 kg and moment ofinertia $0.02kgm^{2}$ about its own axis. If the cylinder rolls without slipping, then linear acceleration of its centre of mass will be

Options:

A) $6.7m/s^{2}$

B)$10m/s^{2}$

C) $3.3m/s^{2}$

D)None of these

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Answer:

Correct Answer: A

Solution:

[a] Let friction force = f $F+f=ma$- (i) $(F-f)R=I\alpha $- (ii) $

From $eq^{n}s.$ (i) and (ii),

$2F=ma+\frac{I\alpha }{R}$

$Use\alpha =\frac{a}{R}$(for pure rolling)

$2F=ma+\frac{Ia}{R^{2}}$ $40=4a+\frac{0.02a}{{{(0.1)}^{2}}};$

$a=\frac{40}{6}=6.7m/s^{2}$



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