Rotational Motion Question 215

Question: Four identical thin rods each of mass M and lengthl , form a square frame. Moment of inertia of this frame about an axis through the centre of the square and perpendicular to its plane is :

Options:

A) 23Ml2

B) 133Ml2

C) 13Ml2

D) 43Ml2

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Answer:

Correct Answer: D

Solution:

[d] Moment of inertia of a thin rod of length l about an axis passing through centre and perpendicular to the rod =112Ml2

Thus moment of inertia of the frame.

ml212+ml24=4ml212=ml23

Total M.I. =4×ml23



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