SATHEE: Rotational Motion Question 214

Rotational Motion Question 214

Question: A particle of mass m is attached to q a thin uniform rod of length a and mass 4 m. The distance of the particle from the centre of mass of the rod is a/4. The moment of inertia of the combination about an axis passing through 0 normalto the rod is

Options:

A) $\frac{64}{48} m a^{2}$

B) $\frac{91}{48} m a^{2}$

C) $\frac{27}{48} m a^{2}$

D) $\frac{51}{48} m a^{2}$

Show Answer

Answer:

Correct Answer: B

Solution:

[b] Moment of inertia $= m {(\frac{3 a}{4})}^{2} + m_{1} \frac{a^{2}}{3}$

For the centre of rod $(\frac{m_{1} a^{2}}{12} + \frac{m_{1} a^{2}}{4}) = \frac{m_{1} a^{2}}{3}$

$∴ m_{1} = 4 m$

Total $I = m {(\frac{3 a}{4})}^{2} + \frac{4 m a^{2}}{3}$ $= \frac{9 m a^{2}}{16} + \frac{4 m a^{2}}{3}$ $= \frac{(27 + 64)}{48} m a^{2} = \frac{91}{48} m a^{2}$

Rotational Motion Question 214

Question: A particle of mass m is attached to q a thin uniform rod of length a and mass 4 m. The distance of the particle from the centre of mass of the rod is a/4. The moment of inertia of the combination about an axis passing through 0 normalto the rod is

Options:

Answer:

Solution:

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Rotational Motion Question 214

Question: A particle of mass m is attached to q a thin uniform rod of length a and mass 4 m. The distance of the particle from the centre of mass of the rod is a/4. The moment of inertia of the combination about an axis passing through 0 normalto the rod is

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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