SATHEE: Rotational Motion Question 208

Rotational Motion Question 208

Question: A solid cylinder of mass 50 kg and radius 0.5 m is free to rotate about the horizontal axis. A massless string is wound round the cylinder with one end attached to it and other hanging freely. Tension in the string required to produce an angular acceleration of 2 revolutions $s^{- 2}$ is

Options:

A) 25 N

B) 50 N

C) 78.5 N

D) 157 N

Show Answer

Answer:

Correct Answer: D

Solution:

[d]

Here $α = 2 r e v o l u t i o n s / s^{2} = 4 π r a d / s^{2}$

$(g i v e n)$

$I_{c y l i n d e r} = \frac{1}{2} M R^{2} = \frac{1}{2} (50) {(0.5)}^{2}$ $=$ $\frac{25}{4} K g - m^{2}$

$A s$ $τ = I α s o T R = I α$

$\Rightarrow T = \frac{I α}{R} = \frac{(\frac{25}{4}) (4 π)}{(0.5)} N = 50 π N = 157 N$

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Rotational Motion Question 208

Question: A solid cylinder of mass 50 kg and radius 0.5 m is free to rotate about the horizontal axis. A massless string is wound round the cylinder with one end attached to it and other hanging freely. Tension in the string required to produce an angular acceleration of 2 revolutions s−2 is

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Answer:

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Question: A solid cylinder of mass 50 kg and radius 0.5 m is free to rotate about the horizontal axis. A massless string is wound round the cylinder with one end attached to it and other hanging freely. Tension in the string required to produce an angular acceleration of 2 revolutions $s^{- 2}$ is