SATHEE: Rotational Motion Question 200

Rotational Motion Question 200

Question: A hollow sphere of mass 2 kg is kept on a rough horizontal surface. A force of 10 N is applied at the centre of the sphere . Find the minimum value $μ$ so that the sphere starts pure rolling. ( $T a k e g = 10 m / s^{2}$ )

Options:

A) $\sqrt{3} \times 0.16$

B) $\sqrt{3} \times 0.08$

C) $\sqrt{3} \times 0.1$

D) Data insufficient

Show Answer

Answer:

Correct Answer: B

Solution:

[b]

$10 \cos 30^{o} - f = 2 a$ ..(i)

$τ = I α$

$\Rightarrow f_{r} = \frac{2}{3} \times 2 \times r^{2} \times α$ .. (ii)

(where r is radius of sphere) From (i) and (ii), we get $f = 2 \sqrt{3}$ newton,

$N = 20 + 10 \sin 30^{o} = 25$

$f = μ N \Rightarrow μ = \frac{f}{N} = \frac{2 \sqrt{3}}{25} = 0.08 \times \sqrt{3}$

Rotational Motion Question 200

Question: A hollow sphere of mass 2 kg is kept on a rough horizontal surface. A force of 10 N is applied at the centre of the sphere . Find the minimum value $μ$ so that the sphere starts pure rolling. ( $T a k e g = 10 m / s^{2}$ )

Options:

Answer:

Solution:

Engineering Preparation

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NCERT Books & Solutions

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Sample Mock Test

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NCERT Exercise Video Solution

Rotational Motion Question 200

Question: A hollow sphere of mass 2 kg is kept on a rough horizontal surface. A force of 10 N is applied at the centre of the sphere . Find the minimum value μ so that the sphere starts pure rolling. (Takeg=10m/s2 )

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: A hollow sphere of mass 2 kg is kept on a rough horizontal surface. A force of 10 N is applied at the centre of the sphere . Find the minimum value $μ$ so that the sphere starts pure rolling. ( $T a k e g = 10 m / s^{2}$ )