Rotational Motion Question 20

Question: A small particle of mass m is projected at an angle θ with the x-axis with an initial velocity v0 in the xy plane . At a time t<v0sinθg, the angular momentum of the particle is -

[AIEEE 2010]

Options:

A) 12mgv0t2cosθi^

B) mgv0t2cosθj^

C) mgv0tcosθk^

D) 12mgv0t2cosθk^

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Answer:

Correct Answer: D

Solution:

  • [d] at any time t So, where i^,j^ and k^ are unit vectors along x,y and z-axis respectively.

    L=m(r×v)=12mgv0t2cos(θ)k

    r=v0cos(θ)ti+(v0sin(θ)t12gt2)j

    (m) represents mass.

    v=v0cos(θ)i+(v0sin(θ)gt)j



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