Rotational Motion Question 197

Question: Four point masses, each of value m, are placed at the comers of a square ABCD of side $\ell $ .The moment of inertia of this system about an axis passing through A and parallel to BD is

Options:

A) $2m{{\ell }^{2}}$

B) $\sqrt{3}m{{\ell }^{2}}$

C) $3m{{\ell }^{2}}$

D) $m{{\ell }^{2}}$

Show Answer

Answer:

Correct Answer: C

Solution:

[c]

${{I} _{nn’}}=M.I$

due to the point mass at B+M.I

due to the point mass at $D+M.I$

due to the point mass at C.$=2\times m{{\left( \frac{\ell }{\sqrt{2}} \right)}^{2}}+m{{(\sqrt{2}\ell )}^{2}}=m{{\ell }^{2}}+2m{{\ell }^{2}}=3m{{\ell }^{2}}$



NCERT Chapter Video Solution

Dual Pane