Rotational Motion Question 194

Question: The ratio of the radii of gyration of a circular disc about a tangential axis in the plane of the disc and of a circular ring of the same radius about a tangential axis in the plane of the ring is

Options:

A) $1:\sqrt{2}$

B) l : 3

C) 2: l

D) $\sqrt{5}:\sqrt{6}$

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Answer:

Correct Answer: D

Solution:

[d]

$ I _{y_1}=\frac{M R^2}{4} $

$ \therefore I^{\prime} y_1=\frac{M R^2}{4}+M R^2=\frac{5}{4} M R^2 .$

$ I _{y_2}=\frac{M R^2}{2} $

$ \therefore I _{y_2}^{\prime}=\frac{M R^2}{2}+M R^2=\frac{3}{2} M R^2 $

$ I^{\prime} y_1=M K_1^2, I^{\prime} y_2=M K_2^2 $

$ \therefore \quad \frac{K_1^2}{K_2^2}=\frac{I _{y_1}^{\prime}}{I^{\prime} y_2} \Rightarrow K_1: K_2=\sqrt{5}: \sqrt{6} $



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