SATHEE: Rotational Motion Question 189

Rotational Motion Question 189

Question:If $I_{x y}$ is the moment of inertia of a ring about a tangent in the plane of the ring and $I_{x^{'} y^{'}}$ is the moment of inertia of a ring about a tangent perpendicular to the plane of the ring then

Options:

A) $I_{x y} = I_{x^{'} y^{'}}$

B) $I_{x y} = \frac{1}{2} I_{x^{'} y^{'}}$

C) $I_{x^{'} y^{'}} = \frac{3}{4} I_{x y}$

D) $I_{x y} = \frac{3}{4} I_{x^{'} y^{'}}$

Show Answer

Answer:

Correct Answer: D

Solution:

[d]

$I_{x y}$ , moment of inertia of a ring about its tangent in the plane of ring

$I_{x^{'} y} = \frac{3}{2} M R^{2}$ .

Moment of inertia about a tangent perpendicular to the plane of ring

$I_{x y} = 2 M R^{2}$

$∴ I_{x y} = \frac{3}{4} (2 M R^{2}) o r I_{x y} = \frac{3}{4} I_{x^{1} y^{1}}$

Privacy Policy

Powered by Prutor@IITK

sathee@iitk.ac.in

Media coverage of SATHEE

Play Store

App Store

Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on "I understand".

Rotational Motion Question 189

Question:If Ixy is the moment of inertia of a ring about a tangent in the plane of the ring and Ix′y′ is the moment of inertia of a ring about a tangent perpendicular to the plane of the ring then

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Menu

Question:If $I_{x y}$ is the moment of inertia of a ring about a tangent in the plane of the ring and $I_{x^{'} y^{'}}$ is the moment of inertia of a ring about a tangent perpendicular to the plane of the ring then