SATHEE: Rotational Motion Question 186

Rotational Motion Question 186

Question: Linear acceleration of hallow cylinder of mass $m_{2}$ is $a_{2}$ Then angular acceleration $α_{2}$ is (given that there is no slipping).

Options:

A) $\frac{a_{2}}{R}$

B) $\frac{(a_{2} + g)}{R}$

C) $\frac{2 (a_{2} + g)}{R}$

D) None of these

Show Answer

Answer:

Correct Answer: C

Solution:

[c]

$m_{2} g - T = m_{2} a_{2} . . (i)$

$T R = \frac{m_{2} R^{2}}{2} α_{2} . . (ii)$

$α_{1} R = a_{2} - α_{2} R . . (iii)$

$T R = (\frac{m_{1} R^{2}}{2}) α_{1} . . (iv)$

$α_{2} = \frac{2 T}{m_{2} R} = \frac{2}{m_{2} R} \cdot (m_{2} a_{2} + m_{2} g)$

$= 2 (\frac{(a_{2} + g)}{R})$

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Rotational Motion Question 186

Question: Linear acceleration of hallow cylinder of mass m2 is a2 Then angular accelerationα2 is (given that there is no slipping).

Options:

Answer:

Solution:

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Question: Linear acceleration of hallow cylinder of mass $m_{2}$ is $a_{2}$ Then angular acceleration $α_{2}$ is (given that there is no slipping).