Rotational Motion Question 184

Question: Moment of inertia of a circular wire of mass M and radius R about its diameter is

Options:

A) $MR^{2}/2$

B) $MR^{2}$

C) $2MR^{2}$

D) $MR^{2}/4$

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Answer:

Correct Answer: A

Solution:

[a] Perp axis theorem

$I _{x}+I _{y}=I _{z}$

$\Rightarrow 2I=MR^{2}$

So

$I=\frac{MR^{2}}{2}$



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