Rotational Motion Question 184
Question: Moment of inertia of a circular wire of mass M and radius R about its diameter is
Options:
A) $MR^{2}/2$
B) $MR^{2}$
C) $2MR^{2}$
D) $MR^{2}/4$
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Answer:
Correct Answer: A
Solution:
[a] Perp axis theorem
$I _{x}+I _{y}=I _{z}$
$\Rightarrow 2I=MR^{2}$
So
$I=\frac{MR^{2}}{2}$