Rotational Motion Question 182
Question: A wheel of radius 1 m rolls forward half are revolution on a horizontal ground. The magnitude of the displacement of the point of the wheel initially in contact with the ground is
Options:
A) $\pi $
B) $2\pi $
C) $\sqrt{2\pi }$
D) $\sqrt{{{\pi }^{2}}+4}$
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Answer:
Correct Answer: D
Solution:
[d] Linear distance moved by wheel in half revolution $=\pi r$.
Point $P _{1}$ after half revolution reaches at $P _{2}$ vertically 2m above the ground.
$\therefore DisplacementP _{1}P _{2}$
$\sqrt{{{\pi }^{2}}r^{2}+2^{2}}=\sqrt{{{\pi }^{2}}+4}$
$\because r=1m$
