SATHEE: Rotational Motion Question 181

Rotational Motion Question 181

Question: A wheel having angular momentum $2 π k g - m^{2} / s$ about its vertical axis, rotates at the rate of 60 rpm about this axis. The torque which can stop the wheel’s rotation in 30 sec would be

Options:

A) $\frac{π}{18} N m$

B) $\frac{2 π}{15} N m$

C) $\frac{π}{12} N m$

D) $\frac{π}{15} N m$

Show Answer

Answer:

Correct Answer: D

Solution:

[d]

$τ \times Δ t = L_{0}$

$∵ \sin c e L_{f} = 0$

or $τ \times 30 = 2 π$

$τ = \frac{π}{15} N - m$

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Rotational Motion Question 181

Question: A wheel having angular momentum 2πkg−m2/s about its vertical axis, rotates at the rate of 60 rpm about this axis. The torque which can stop the wheel’s rotation in 30 sec would be

Options:

Answer:

Solution:

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Question: A wheel having angular momentum $2 π k g - m^{2} / s$ about its vertical axis, rotates at the rate of 60 rpm about this axis. The torque which can stop the wheel’s rotation in 30 sec would be