Rotational Motion Question 180

Question: Two identical discs of mass m and radius r are arranged . If $\alpha $ is the angular acceleration of the lower disc and $a _{cm}$ is acceleration of centre of mass of the lower disc, then relation between

Options:

A) $a _{cm}=\alpha /r$

B) $a _{cm}=2\alpha r$

C) $a _{cm}=\alpha r$

D) None of these

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Answer:

Correct Answer: B

Solution:

[b]

$ T r=\frac{m r^2}{2} \alpha _1 \text { ..(1) } $

$ \operatorname{Tr}=\frac{m r^2}{2} \alpha \text { …(2) } $

$ \alpha _1=\alpha \text { .. (3) } $

Acceleration of point $\mathrm{b}=$ acceleration of point $\mathrm{a}$

$ r \alpha_1=a _{c m}-r \alpha \text { Hence, } 2 r \alpha=a _{c m} \text { ….(4) } $



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