Rotational Motion Question 179

Question: The moment of inertia of a uniform circular disc of radius ‘R’ and mass ‘M’ about an axis passing from the edge of the disc and normal to the disc is

Options:

A) $MR^{2}$

B) $\frac{1}{2}MR^{2}$

C) $\frac{3}{2}MR^{2}$

D) $\frac{3}{2}MR^{2}$

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Answer:

Correct Answer: C

Solution:

[c] M.I.

of a uniform circular disc of radius ‘R’ and mass ’ $M$ ’ about an axis passing through C.M and normal to the disc is $ I _{C.M.}=\frac{1}{2} M R^2$ From parallel axis theorem

$I_T=I _{C.M .}+M R^2=\frac{1}{2} M R^2+M R^2=\frac{3}{2} M R^2 $



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