Rotational Motion Question 170

Question: The instantaneous angular position of a point on a rotating wheel is given by the equation$\theta (t)=2t^{3}-6t^{2}$ . The torque on the wheel becomes zero at

Options:

A) $t=1s$

B) $t=0.5s$

C) $t=0.25s$

D) $t=2s$

Show Answer

Answer:

Correct Answer: A

Solution:

[a] When angular acceleration

$\alpha $ is zero then torque on the wheel becomes zero.

$\theta (t)=2t^{3}-6t^{2}\Rightarrow \frac{d\theta }{dt}=6t^{2}-12t$

$\Rightarrow \alpha =\frac{d^{2}\theta }{dt^{2}}=12t-12=0\therefore t=1\sec .$



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