SATHEE: Rotational Motion Question 157

Rotational Motion Question 157

Question: The centre of mass of three bodies each of mass 1 kg located at the points (0,0), (3,0) and (0,4) in the XY plane is

Options:

A) $(\frac{4}{3}, 1)$

B) $(\frac{1}{3}, \frac{2}{3})$

C) $(\frac{1}{2}, \frac{1}{2})$

D) $(1, \frac{4}{3})$

Show Answer

Answer:

Correct Answer: D

Solution:

[d]

$X_{C M} = \frac{m_{1} x_{1} + m_{2} x_{2} + m_{3} x_{3}}{m_{1} + m_{2} + m_{3}}$

$= \frac{1 \times 0 + 1 \times 3 + 1 \times 0}{1 + 1 + 1}$

$Y_{C M} = \frac{m_{1} y_{1} + m_{2} y_{2} + m_{3} y_{3}}{m_{1} + m_{2} + m_{3}}$

$= \frac{1 \times 0 + 1 \times 0 + 1 \times 4}{1 + 1 + 1} = \frac{4}{3}$

Therefore the coordinates of centre of mass are

$(1, \frac{4}{3})$

Rotational Motion Question 157

Question: The centre of mass of three bodies each of mass 1 kg located at the points (0,0), (3,0) and (0,4) in the XY plane is

Options:

Answer:

Solution:

Engineering Preparation

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Rotational Motion Question 157

Question: The centre of mass of three bodies each of mass 1 kg located at the points (0,0), (3,0) and (0,4) in the XY plane is

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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