Rotational Motion Question 153
Question: A system consists of three particles, each of mass m and located at (l, 1), (2, 2) and (3, 3). The co- ordinates of the centre of mass are
Options:
A) (1, 1)
B) (2, 2)
C) (3, 3)
D) (6, 6)
Show Answer
Answer:
Correct Answer: B
Solution:
[b] The coordinates of C.M of three particle are
$x=\frac{m _{1}x _{1}+m _{2}x _{2}+m _{3}x _{3}}{m _{1}+m _{2}+m _{3}} $ and
$y=\frac{m _{1}y _{1}+m _{2}y _{2}+m _{3}y _{3}}{m _{1}+m _{2}+m _{3}}$
here
$m _{1}=m _{2}=m _{3}=m$
so
$x=\frac{(x _{1}+x _{2}+x _{3})m}{m+m+m}=2$
$y=\frac{(y _{1}+y _{2}+y _{3})}{m+m+m}=2$
So coordinates of C.M.of three particle are (2,2)
