SATHEE: Rotational Motion Question 148

Rotational Motion Question 148

Question: A solid cylinder of mass m & radius R rolls down inclined plane without slipping. The speed of C.M. when it reaches the bottom is

Options:

A) $\sqrt{2 g h}$

B) $\sqrt{4 g h / 3}$

C) $\sqrt{3 / 4 g h}$

D) $\sqrt{4 g h}$

Show Answer

Answer:

Correct Answer: B

Solution:

[b] By energy conservation

$(K . E)_{i} + (P . E)_{i} = (K . E)_{f} + (P . E)_{f}$

$(K . E)_{i} = 0, (P . E)_{i} = m g h, (P . E)_{f} = 0$

$(K . E)_{f} =_{1 / 2} I ω^{2} +_{1}_{2} m v_{c m}^{2}$

$Where I$ moment of inertia= $1 / 2 m R^{2} (for solid cylinder) so$

$m g h =^{1} / 2 (1 / 2 m R^{2}) (\frac{v^{2} c m}{R^{2}}) +_{1}_{2} m v_{c m}^{2} .$

$\Rightarrow v_{c m} = \sqrt{4 g h / 3}$

Rotational Motion Question 148

Question: A solid cylinder of mass m & radius R rolls down inclined plane without slipping. The speed of C.M. when it reaches the bottom is

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Rotational Motion Question 148

Question: A solid cylinder of mass m & radius R rolls down inclined plane without slipping. The speed of C.M. when it reaches the bottom is

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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