SATHEE: Rotational Motion Question 14

Rotational Motion Question 14

Question: Four point masses, each of value m, are placed at the corners of a square ABCD of side 1. The moment of inertia of this system about an axis passing through A and parallel to BD is

[AIEEE 2006]

Options:

A) $2 m l^{2}$

B) $\sqrt{3} m l^{2}$

C) $3 m l^{2}$

D) $m l^{2}$

Show Answer

Answer:

Correct Answer: C

Solution:

[c] $I_{A}$ = 0

$I_{B} = I_{D}$ = $m r^{2}$

= $m {\frac{l}{\sqrt 2}}^{2}$

= $\frac{m l^{2}}{2}$

$I C = m (\sqrt 2 l)^{2}$

$I C = 2 m l^{2}$

$I = I_{A} + I_{B} + I_{C} + I_{D}$

$I = 0 + \frac{m l^{2}}{2} + \frac{m l^{2}}{2} + 2 m l^{2}$

$I = 3 m l^{2}$

Play Store

App Store

Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on "I understand".

Rotational Motion Question 14

Question: Four point masses, each of value m, are placed at the corners of a square ABCD of side 1. The moment of inertia of this system about an axis passing through A and parallel to BD is

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Menu