Rotational Motion Question 132

Question:A cube of side $a$ is placed on an inclined plane of inclination $\theta $ . What is the maximum value of 9 for which the cube will not topple?

Options:

A) $15{}^\circ $

B) $30{}^\circ $

C) $45{}^\circ $

D) $69{}^\circ $

Show Answer

Answer:

Correct Answer: C

Solution:

[c] The cube will not topple until the line of action of CM passes through the cube.

That is, $\tan \theta =\frac{AX}{OX}=\frac{a/2}{a/2}$ or $\theta =45{}^\circ $



NCERT Chapter Video Solution

Dual Pane